AP Statistics / Mr. Hansen

Name: _________________________________

Corrected Answer Key (4/26/99) for "Inference for Regression" Worksheets
(sketches of solutions, with most of the work and details missing)

Note:

(1)

Scatterplot shows positive linear relationship. Check residual plot, too—no patterns evident.*

(2)

xbar = 55, ybar = 52.333, sx = 18.708, sy = 7.367

(3)

r = 0.958, yhat(x) = 31.590 + 0.377x

(4)

0.958 (7.367/18.708) = 0.377 ü

(5)

s2 = MSE = 5.605

(6)

sb1 = 0.0566 (note corrected value)

(7)

(0.220, 0.534)

(8)

There is good evidence (t = 6.664, df = 4, P = 0.0013) to reject H0 in favor of the one-sided alternative.

(9)

omit

1.

b1 = 0.15428; check scatterplot to verify positive linear association, residual plot to verify absence of patterns*

2.

t = 12.503, p = 0.000008

3.

sb1 = 0.01234

4.

(0.124, 0.184) (note corrected values)

5.

omit

1.(a)

y = –310.999 + 150.894x; check scatterplot to verify positive linear association, residual plot to verify absence of patterns*

(b)

SSE = 97,361.232

(c)

sb1 = 17.152

(d)

H0: b = 0
Note: Normally we would say b1 instead of b, but the preamble for this problem used b to denote the true slope.

(e)

(114.53, 187.25)

(f)

There is strong evidence (t = 8.798, df = 16, P = 0.00000008) to reject H0 in favor of the one-sided alternative Ha: b >0.

2.(a)

First, check scatterplot to verify negative linear association, and check residual plot to verify absence of patterns.*
H0: b1 = 0
Ha: b1 < 0
There is good evidence (t = –3.096, df = 6, P = 0.0106) that image quality is negatively associated with average reading time.

(b)

H0: b1 = –0.25
Ha: b1 ¹ –0.25
There is no evidence (t = –0.875, df = 6, P = 0.415) that the slope differs from –0.25. (Of course, this doesn’t prove b1 = –0.25. All we can say is that there is insufficient evidence to reject that hypothesis.)