A Solution to #92 from Practice Exam
Note: There may be an easier way, but I have not found it yet!
Apply the formula you learned in Honors Precal for
the partial sum of a geometric series with first term a and common ratio r,
namely that the sum of n terms of the
geometric series equals 
. This gives
[*]
The second factor in the expression marked [*] is a limit of form 
(L’Hôp.),
and that limit becomes
The final answer from [*] above, after substituting for the
limit, is therefore (1 − e2)(−1)
= e2 − 1 
6.389.