Geometry / Mr. Hansen |
Name: _______________________________________ |
12/8/2007 |
|
Answers to Selected Problems
Warning: For best results, you should
peek at these answers only
after attempting the problems on your own, under time pressure.
p. 323 |
1. Look at
|
|
|
2. Now look at |
|
|
3. Now look at |
|
|
4. Solve for a in the result of step 3 to get a = 90 – (b + d)/2. |
|
|
5. Substitute the result of
step 4 into step 2 to get h = 90 – a = 90 – (90 – (b + d)/2) = (b + d)/2. (Q.E.D.) |
|
|
|
|
|
If this problem, or one
similar to it, were featured on the test, you would be able to earn
considerable partial credit merely by writing the “forward chaining” equations
in steps 1 and 2. In other words, you use the only things that you know to
apply here, which are that the angles in various triangles must add up to 180°. |
|
|
|
|
|
Earning full credit is a
bit more challenging, since you have to be able to use your algebra skills in
a creative way to solve a problem. This is harder than the problems you saw
in Algebra I, where you were told exactly what to do and when to do it. |
|
|
|
|
p. 290 |
____________________________________________________________________________________ |
|
|
1. |
| 1. Given |
|
2. |
| 2. Given |
|
3. |
| 3. ITT |
|
4. |
| 4. Refl. |
|
5. Angles PQA and PQB are
rt. |
| 5. Def. |
|
6. |
| 6. HL (3, 4) |
|
7. |
| 7. CPCTC |
|
8. |
| 8. Refl. |
|
9. Angles AQR and BQR are
rt. |
| 9. Def. |
|
10. Angles AQR and BQR are |
| 10. All rt. |
|
11. |
| 11. SAS (7, 10, 8) |
|
12. |
| 12. CPCTC |
|
13. |
| 13. Refl. |
|
14. |
| 14. SSS (3, 12, 13) |
|
15. |
| 15. CPCTC |
|
(Q.E.D.) |
|