Monthly Schedule

(IntroCal, Period B)

Th 3/1/07

HW due: §5.2 #13-27 odd. Work (including a sketch in most cases) is required. Check your answers in the back of the book and/or by using MATH 9. The style of solution is illustrated on p. 750 for #13. Use that style of solution throughout.

In class: Second viewing of the tenth dimension video.

 

F 3/2/07

HW due: Read §5.3; write §5.2 #41-46 all.

Note for #41-42: Be sure to show the setup using integral notation. (No credit for answer without setup.)

Note for #43-46 all: Use MATH 9 to double-check your answers. Graphs are required for each one, and your point(s) of discontinuity should be clearly shown.

Note for #44: The “int” function is referring to the greatest integer function, which can be found on your calculator under 2nd CATALOG. The notation int(x) means the greatest integer less than or equal to x. For example, int(3.218) = 3, int(–5.118) = –6, int(7.9999) = 7, and int(k) = k whenever k is an integer.

 

M 3/5/07

Double Quiz on FTC and area calculations using definite integrals, including MATH 9.

There is no additional written work due today.

 

T 3/6/07

Oops! No additional HW since it was not posted in time. If you wish, you may read pp. 268-274, which we started to cover yesterday in class.

 

W 3/7/07

Quest (70 pts.) on FTC, Definite Integrals, and Optimization. If for some reason school is canceled today, the quest will be provided to you as a take-home quest due Thursday.

Mean value of a function (yellow box on p. 271) will also be on the quest. See §5.3 #25-29 for examples of problems of this type. Since the mean value formula has not been covered in class, it will be provided for you.

Example problem:

Compute the average (mean) value of the sine function over the interval [
p/6, 2p/3] by applying the formula . Use FTC, showing your work, and check your answer.


Solution:





Check: MATH 9 sin(x),x,
p/6,2p/3 gives 1.366 . . . , which yields 0.870 when divided by (2p/3 – p/6). ü

 

Th 3/8/07

HW due: Read pp. 268-274; rewrite questions #1-5 from yesterday’s quest. On a separate sheet of paper, write question #6 from yesterday’s quest. You may work together on #1-5 but not on #6. If you wish to have #6 graded and attached to your quest score, you must sign a statement at the top of your #6 sheet saying that you worked alone on the problem. (Otherwise, the problem will be scored only as homework, and the quest will be scored as originally submitted.)

The answer to #6 is approximately 26.5 units, but you get no credit for that answer. You need to show work supported by integral(s). A diagram is strongly suggested. As always, your final answer must be correct to at least 3 decimal places.

 

F 3/9/07

Last day of quarter. We celebrate by having no additional HW due. Hooray!

 

M 3/12/07

Form VI Career Day—class canceled for everyone.

 

T 3/13/07

Quiz (10 pts.) on the rules on p. 269 and the yellow box on p. 271.

No additional HW due today. However, be sure you have read pp. 268-274 if you have not already done so. Reading notes are required, as always.

 

W 3/14/07

HW due: §5.3 #2, 4, 6, 25-28 all.

 

Th 3/15/07

HW due: Read §5.4, especially Example 4 and the top half of p. 280 (up to the boldface subheading). Written assignment:

1.(a) First, note that on p. 282, the statement that your book calls FTC2 (which we learned previously) is proved by means of FTC1. In fact, the very first sentence in the proof says “Part 1 of the Fundamental Theorem tells us . . .” We may summarize this proof by saying that the truth of what your book calls FTC1 allows us to prove the truth of FTC2. In other words, FTC1 implies FTC2. Write this, using mathematical notation.

(b) Prove that FTC2 implies FTC1. In other words, show that if you take the entire yellow box on p. 282 as a given (which should be easy to do, since you have been quizzed on this several times and know it thoroughly by now), then the equation at the end of the yellow box on p. 277 is true. Do not use the proof that your book gives you on pp. 277-278, which is long and difficult. Use a simpler approach that takes advantage of the FTC that you already learned. Your proof should be no more than about 4 lines long. Give a reason for each step.

If the word “prove” frightens you, then start with the expression  and simplify it.

Your goal is to obtain f (x) by providing a valid reason for each step.

(c) The outcome of part (a) is that FTC1
Ž FTC2. The outcome of part (b), whether you were successful or not, is that FTC2 Ž FTC1. What do (a) and (b) say, if you take them together as a pair?

2. Yesterday’s assignment may be collected and scanned a second time. Do not throw away points!

 

F 3/16/07

HW due: Do all 7 problems, even #1. For #1, all you need to do is copy my work for the two solution methods, but you must do both of them.

1. Find a function G(x) whose derivative is e3x if it is given that G(2.3) = –1.8.

Solution: By FTC1, e3x has an antiderivative, namely .

The lower limit of integration is chosen to make our lives easy, and the required value of C is clearly –1.8, since an integral from 2.3 to 2.3 is 0. With practice, we can solve problems like this by inspection. Answer: .

Solution (alternate method): A general antiderivative of e3x is . Plug in x = 2.3 and write

the equation that must be true: . By simple algebra [show the steps when

you write this up], C
» –332.558. Final answer: .

2. Explain why method 1 for #1 is better. Hint: Think of what might happen if the given derivative was something for which one could not easily find an antiderivative by the techniques we learned earlier in the year.

3. Find a function H(x) whose derivative is sin x if it is given that H(–11) = –3.18. Use both methods.

4. Find a function K(x) whose derivative is cos2 x if it is given that K(3.17) = 11.458. Use whichever method you prefer.

5. Find a function L(x) whose derivative is tan xln x if it is given that L(4) = 8. Use whichever method you prefer.

6. Find a function M(x) whose derivative is 7x cos x if it is given that M(2.99) =
p. Use whichever method you prefer.

7. I am thinking of a function N(x) whose derivative is –15ecos x + 2. I will tell you that N(3) = 7.188. Problem: Find N(3.2).

Hint for #7: First, find N(x). Then, use your calculator to plug in and find N(3.2).

 

 


Return to the IntroCal Zone

Return to Mr. Hansen’s home page

Return to Mathematics Department home page

Return to St. Albans home page

Last updated: 17 Mar 2007