Solution Key to Practice Proofs for Final Exam
rev. 5/19/2001
I. |
Statement |
Reason |
|
1. m(arc DB) = m(arc BE) |
1. Given |
|
2. ÐDAB @ ÐEAB |
2. Inscr. Ðs intercepting @ arcs must be @ |
|
3. sAB is a diameter of ¤C |
3. Given |
|
4. ÐD is a rt. Ð |
4. Ð inscr. in a semicircle |
|
5. ÐE is a rt. Ð |
5. " |
|
6. ÐD @ ÐE |
6. All rt. Ðs are @ |
|
7. sAB @ sAB |
7. Reflexive |
|
8. DDAB @ DEAB |
8. AAS |
|
9. sAD @ sAE |
9. CPCTC |
II. |
Statement |
Reason |
|
1. ÐEDC @ ÐB |
1. Given |
|
2. ÐC @ ÐC |
2. Reflexive |
|
3. ÐDEC @ ÐA |
3. No-Choice Thm. (looking at third Ð of DEDC and of DABC) |
II. (alt.) |
Statement |
Reason |
|
1. ÐEDC @ ÐB |
1. Given |
|
2. ÐC @ ÐC |
2. Reflexive |
|
3. DEDC ~ DABC |
3. AA~ |
|
4. ÐDEC @ ÐA |
4. Corresp. Ðs of similar Ds are @ |
III. |
Statement |
Reason |
|
1. sAB and sBC are tangent to ¤Q |
1. Given |
|
2. AD > DC |
2. Given |
|
3. sAB @ sCB |
3. Tangents from an external pt. are @ |
|
4. sDB @ sDB |
4. Reflexive |
|
5. mÐABD > mÐDBC |
5. Converse Hinge Thm. (or SSS¹); acceptable to say Hinge Thm. |
After you have studied these proofs, be sure to check out the 2-column proof that girls are evil.