Solution Key to Practice Proofs for Final Exam
rev. 5/19/2001
| I. | 
 Statement  | 
 Reason  | 
| 
 
  | 
 1. m(arc DB) = m(arc BE)  | 
 1. Given  | 
| 
 
  | 
 2. ÐDAB @ ÐEAB  | 
 2. Inscr. Ðs intercepting @ arcs must be @  | 
| 
 
  | 
 3. sAB is a diameter of ¤C  | 
 3. Given  | 
| 
 
  | 
 4. ÐD is a rt. Ð  | 
 4. Ð inscr. in a semicircle  | 
| 
 
  | 
 5. ÐE is a rt. Ð  | 
 5. "  | 
| 
 
  | 
 6. ÐD @ ÐE  | 
 6. All rt. Ðs are @  | 
| 
 
  | 
 7. sAB @ sAB  | 
 7. Reflexive  | 
| 
 
  | 
 8. DDAB @ DEAB  | 
 8. AAS  | 
| 
 
  | 
 9. sAD @ sAE  | 
 9. CPCTC  | 
| 
 II.  | 
 Statement  | 
 Reason  | 
| 
 
  | 
 1. ÐEDC @ ÐB  | 
 1. Given  | 
| 
 
  | 
 2. ÐC @ ÐC  | 
 2. Reflexive  | 
| 
 
  | 
 3. ÐDEC @ ÐA  | 
 3. No-Choice Thm. (looking at third Ð of DEDC and of DABC)  | 
| 
 II. (alt.)  | 
 Statement  | 
 Reason  | 
| 
 
  | 
 1. ÐEDC @ ÐB  | 
 1. Given  | 
| 
 
  | 
 2. ÐC @ ÐC  | 
 2. Reflexive  | 
| 
 
  | 
 3. DEDC ~ DABC  | 
 3. AA~  | 
| 
 
  | 
 4. ÐDEC @ ÐA  | 
 4. Corresp. Ðs of similar Ds are @  | 
| 
 III.  | 
 Statement  | 
 Reason  | 
| 
 
  | 
 1. sAB and sBC are tangent to ¤Q  | 
 1. Given  | 
| 
 
  | 
 2. AD > DC  | 
 2. Given  | 
| 
 
  | 
 3. sAB @ sCB  | 
 3. Tangents from an external pt. are @  | 
| 
 
  | 
 4. sDB @ sDB  | 
 4. Reflexive  | 
| 
 
  | 
 5. mÐABD > mÐDBC  | 
 5. Converse Hinge Thm. (or SSS¹); acceptable to say Hinge Thm.  | 
After you have studied these proofs, be sure to check out the 2-column proof that girls are evil.